Question

factorize:(5p-7q)²+140pq​

Answer 1

Answer:

by using identity

(a-b)^2=a^2+b^2-2ab

(5p-7q)^2=(5p)^2+(7q)^2-2×(5p)×(7q) +140pq

(5p-7q)^2=25p^2+49q^2-70pq+140pq

(5p-7q)^2=25p^2+49q^2+70pq .

Step-by-step explanation:

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