Question

Factorize: (5x+2)²-16

please tell me the answer asap

Answer 1

Answer:

Judging

Step-by-step explanation:

Answer 2

Answer:

$x = \frac{2}{5} , \frac{-6}{5}$

Step-by-step explanation:

The equation is $(5x+2)^{2} -16 = 0$

Applying $(a+b)^{2} = a^{2} +b^{2} +2ab$

⇒ $[(5x)^{2} +(2)^{2} +2(5x)(2)] - 16 = 0$

⇒ $[25x^{2} + 4 + 20x]-16 = 0$

⇒ $25x^{2} +20x-12 = 0$

We can split $20x$ as $(30x-10x)$

⇒ $25x^{2} + 30x - 10x -12 = 0$

⇒ $5x(5x+6)-2(5x+6) = 0$

⇒ $(5x-2)(5x+6) = 0$

This means that $5x-2 = 0, 5x+6 = 0$

⇒ $5x-2 = 0$  ;  $5x+ 6 = 0$

⇒ $5x = 2$        ;  $5x = -6$

⇒ $x=\frac{2}{5}$          ;  $x = \frac{-6}{5}$

∴ $x = \frac{2}{5} , \frac{-6}{5}$