Question

factorize 64-a3b3+8-2ab​

Answer 1

Step-by-step explanation:

(4-ab)(a

2

b

2

+4ab+18)

Step-by-step explanation:

\begin{gathered}64-a^3b^3+8-2ab\\=4^3-(ab)^3+2(4-ab)\\=(4-ab)(16+4ab+(ab)^2)\end{gathered}

64−a

3

b

3

+8−2ab

=4

3

−(ab)

3

+2(4−ab)

=(4−ab)(16+4ab+(ab)

2

)

( ∵ a^3-b^3=(a-b)(a^2+ab+b^2)a

3

−b

3

=(a−b)(a

2

+ab+b

2

) )

\begin{gathered}=(4-ab)(16+4ab+(ab)^2+2)\\=(4-ab)(18+4ab+(ab)^2)\end{gathered}

=(4−ab)(16+4ab+(ab)

2

+2)

=(4−ab)(18+4ab+(ab)

2

)