factorize 64a^6 - 729b^6
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11
Answer:
64a^6 - 729b^6
a⁶-b⁶ = (a²)³-(b²)³
a⁶ =64a⁶ b⁶ = 729b⁶
a = 2a b=3b
a⁶-b⁶=(a²-b²)(a⁴+a²b²+b⁴)
64a⁶-729b⁶= (4a²-9b²)(16a⁴+36a²b²+81b⁴)
=(2a+3b)(2a-3b)(16a⁴+36a²b²+81b⁴)
Step-by-step explanation:
a³-b³=(a-b)(a²+ab+b²)
a⁶-b⁶=(a²-b²)(a⁴+a²b²+b⁴)
a²-b²=(a+b)(a-b)
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9
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Answer:hope it helps you and please mark as brainliest
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