factorize 64x3+ root125y3
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(4x^3)^3 + (5y^3)^3
.: a^3+b^3=(a+b)(a^2-ab+b^2)
here a=4x
b=5y
(8x+5y)(4x^2-4x*5y+5y^2)
(8x+5y)(16x^2-20xy+25y^2)
you can solve it further
.: a^3+b^3=(a+b)(a^2-ab+b^2)
here a=4x
b=5y
(8x+5y)(4x^2-4x*5y+5y^2)
(8x+5y)(16x^2-20xy+25y^2)
you can solve it further
Answered by
2
@
64x³+√125y³
=> (4x)³ + (√5y)³
=> (4x+√5y) ( 16x² + 5y² - 4√5xy ) Ans
@:-)
64x³+√125y³
=> (4x)³ + (√5y)³
=> (4x+√5y) ( 16x² + 5y² - 4√5xy ) Ans
@:-)
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