Question

Factorize:
6ab-b²+12ac-2bc

Answer 1

The expression is given as : 6ab - b² + 12ac - 2bc

Firstly we regroup these terms to factorise :  

6ab + 12ac - b² - 2bc

Here , in the given expression 6a is common factor in 6ab + 12ac and - b is common factor in - b² - 2bc  :  

= 6a(b + 2c) – b(b + 2c)

Taking (b + 2c) common factor :  

= (b + 2c) (6a – b)

Hence,  the factorisation of 6ab - b² + 12ac - 2bc  is  (b + 2c) (6a – b).

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Answer 2

Answer:

Step-by-step explanation:

Firstly we regroup these terms to factorise :  

6ab + 12ac - b² - 2bc

Here , in the given expression 6a is common factor in 6ab + 12ac and - b is common factor in - b² - 2bc  :  

= 6a(b + 2c) – b(b + 2c)

Taking (b + 2c) common factor :  

= (b + 2c) (6a – b)