Question

factorize 6x^2 + 17x + 5 by using factor theorem

Answer 1

6x²+ 17x+ 5

= 6x²+ 2x + 15x + 5

= 2x( 3x+ 1) 5( 3x + 1)

= (2x+ 5) +( 3x+1)

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Answer 2

Step-by-step explanation:

f(x) =6x²+17x+5

=6x²+(15+2)x+5

=6x²+15x+2x+5

=3x(2x+5)+1(2x+5)

=(3x+1)(2x+5)

x= -1/3 , -5/2

f(x) = 6x²+17x+5

f(-1/3) = 6(-1/3)²+17×-1/3+5

f(-1/3) = 6×1/9-17/3+5

f(-1/3) = 2/3-17/3+5

f(-1/3) = (2-17+15)/3

f(-1/3) = 0

Hence, f(-1/3) is a factor of f(x) = 6x²+17x+5

f(x) = 6x²+17x+5

f(-5/2) = 6(-5/2)²+17×-5/2+5

f(-5/2) = 6×25/4 - 85/2 +5

f(-5/2) = 75/2-85/2+5

f(-5/2) = (75-85+10)/2

f(-5/2)=0

Hence, f(-5/2) is a factor of f(x) = 6x²+17x+5

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