Question

factorize √7x²-6x-13√7=0

Answer 1

$\sqrt{7} {x}^{2} - 6x - 13 \sqrt{7} \\ \sqrt{7} {x}^{2} - 13x + 7x - 13 \sqrt{7} \\ x( \sqrt{7} x - 13) + \sqrt{7} \sqrt{7} x - 13 \sqrt{7} \\ x( \sqrt{7} x - 13) + \sqrt{7} ( \sqrt{7} x - 13) \\ ( \sqrt{7} x - 13)(x + \sqrt{7} )$

Answer 2

Answer:

(x = 13√7/7) and (x = -√7) are the roots of this quadratic equation.

Step-by-step explanation:

1. √7x^2 - 6x - 13√7 = 0
2. √7x^2 - 13x + 7x - 13√7 = 0
3. x(√7x - 13) + √7(√7x - 13) = 0
4. (√7x - 13) (x + √7) = 0
5. (√7x - 13) = 0 and (x + √7) = 0
6. √7x = 13 and x = -√7
7. x = 13/√7 and x = -√7
8. (x = 13√7/7) and (x = √7) Thank You......