Question

Factorize 8p 3 +12/5p 2 +6/25p+1/125

Answer 1

Answer:

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Answer 2

Answer:

$Factors \:of \\8p^{3}+\frac{12}{5} p^{2}+\frac{6}{25}p+\frac{1}{125}\\=\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)$

Step-by-step explanation:

$Factorisation \: of \:the\\expression :\\8p^{3}+\frac{12}{5} p^{2}+\frac{6}{25}p+\frac{1}{125}\\=\big(2p\big)^{3}+3\times \big(2p\big)^{2}\times \frac{1}{5}+3\times (2p)\times \big(\frac{1}{5}\big)^{2}+\big(\frac{1}{5}\big)^{3}\\=\left(2p+\frac{1}{5}\right)^{3}$

/* By algebraic identity:

a³+3a²b+3ab²+b³ = (a+b)³ */

$=\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)$

Therefore,

$Factors<strong> </strong>\:of \\8p^{3}+\frac{12}{5} p^{2}+\frac{6}{25}p+\frac{1}{125}\\=\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)\left(2p+\frac{1}{5}\right)$

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