Question

factorize 8x^3-27y^3+x^3+18xyz

Answer 1

holla buddy


here is ur answer


Given 8x3 + y3 + 27z3 – 18xyz = (2x)3 + y3+ (3z)3 – 3(2x)(y)(3z) It is in the form of a3 + b3 + c3 – 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca) Hence, (2x)3 + y3 + (3z)3 – 3(2x)(y)(3z) = (2x + y + 3z)[(2x)2 + y2 +(3z)2 – (2x)y – y(3z) – (3z)x]                                                              = (2x + y + 3z)[4x2 + y2 + 9z2 – 2xy – 3yz – 3zx]

Answer 2

Can someone go and answer my recent question? And the answer is:

9(x3+2xyz−3y3)