Question

factorize 9(2a-b)²-4(2a-b)-13​

Answer 1

Step-by-step explanation:

Given 9(2a – b)2 – 4(2a – b) – 13 Put (2a – b) = k Hence 9(2a – b)2 – 4(2a – b) – 13 = 9k2 – 4k – 13 = 9k2 – 13k + 9k – 13 = k(9k – 13) + 1(9k – 13) = (9k – 13)(k + 1) = [9(2a – b) – 13)[(2a – b) + 1] = [18a – 9b – 13)[2a – b + 1]