Question

factorize
9(a-2)^2-16(a+2)^2

Answer 1

Step-by-step explanation:

9(a−2)

2

−16(a+2)

2

=[3(a−2)]

2

−[4(a+2)]

2

9(a−2)

2

−16(a+2)

2

=[3(a−2)−4(a+2)][3(a−2)+4(a+2)] [∴a

2

−b

2

=(a+b)(a−b)]

9(a−2)

2

−16(a+2)

2

=[3a−6−4a−8][3a−6+4a+8]

9(a−2)

2

−16(a+2)

2

=[−a−14][7a+2]

9(a−2)

2

−16(a+2)

2

=−[a+14][7a+2]

Answer 2

Answer:

Given Equation is 9(a - 2)^2 - 16(a + 2)^2

[3(a - 2)]^2 - [4(a + 2)]^2

We know that a^2 - b^2 = (a + b)(a - b)

[3(a - 2) + 4(a + 2)][3(a - 2) - 4(a + 2)]

(3a - 6 + 4a + 8)(3a - 6 - 4a - 8)

(7a + 2)(-a - 14)

Step-by-step explanation:

hope my answer help you