Math, asked by SanyaBhasin, 1 year ago

Factorize:.........​

Attachments:

vv1112004: take 2 root 3 and root 3 you will get answers

Answers

Answered by ChayaNH
0

x^2+root3-6=0

=x^2+2root3x-root3x-6

=x (x+2root3)-root3(x+2root3)

=(x-root3)(x+2root3)

×=root3,-2root3

this answer may help you

Answered by AbhijithPrakash
1

Answer:

\large{\underline{x = \bold{\sqrt3, -2\sqrt3}}}

Step-by-step explanation:

x^2 - \sqrt3x - 6 = 0\\\implies x^2 + 2\sqrt3x - \sqrt3x-6=0\\\implies x (x+2\sqrt3)-\sqrt3(x+2\sqrt3)=0\\\implies (x-\sqrt3)(x+2\sqrt3)=0\\\therefore x = \bold{\sqrt3, -2\sqrt3}


AbhijithPrakash: Thanks For Marking my answer as Brainliest!!
SanyaBhasin: welcome
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