Question

Factorize:.........​

Answer 1

x^2+root3-6=0

=x^2+2root3x-root3x-6

=x (x+2root3)-root3(x+2root3)

=(x-root3)(x+2root3)

×=root3,-2root3

this answer may help you

Answer 2

Answer:

$\large{\underline{x = \bold{\sqrt3, -2\sqrt3}}}$

Step-by-step explanation:

$x^2 - \sqrt3x - 6 = 0\\\implies x^2 + 2\sqrt3x - \sqrt3x-6=0\\\implies x (x+2\sqrt3)-\sqrt3(x+2\sqrt3)=0\\\implies (x-\sqrt3)(x+2\sqrt3)=0\\\therefore x = \bold{\sqrt3, -2\sqrt3}$