Question

factorize 9a²+16b²+25c²-24ab-40bc+30ca​

Answer 1

Answer:

(3a-4b+5c)²=(3a-4b+5c)(3a-4b+5c)

Step-by-step explanation:

This equation is in the form (a+b+c)²=a²+b²+c²+2ab+2bc+2ac

(3a)²+(-4b)²+(5c)²+2*3a*-4b +2*-4b*5c+2*3a*5c

therefore :

(3a-4b+5c)(3a-4b+5c)

Answer 2

9a² + 16b² + 25c² - 24ab - 40bc + 30ca

9a² = ( 3a ) ² ; 16b² = ( 4b ) ² ; 25c² = ( 5c ) ²

- 24ab = - 2 x 3a x 4b ; - 40bc = - 2 x 4b x 5c

30ca = 2 x 5c x 3a

Answer ➡ ( 3a - 4b + 5c ) ²