Math, asked by shahilkashyap858, 9 months ago

Factorize:

a^3 + 3a^2b + 3ab^2 + b^3 -8​

Answers

Answered by tushar0007
14

a³ + 3a²b + 3ab² + b³ - 8

= (a³ + 3a²b + 3ab² + b³) - 8

= (a + b)³ - (2)³

= (a + b - 2)[(a + b)² + (2)² + (a + b)(2)]

= (a + b - 2)(a² + b² + 2ab + 4 + 2a + 2b).

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