Factorize (a+b-2c)^3 +(b+c-2a)^3+(a+c-2b)^3
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( a + b -2c ) + (b + c -2a )+ ( c + a -2b) =0
so,
use a³ + b³ + c³ = 3abc
when a + b + c =0
now,
( a + b -2c )³ + ( b + c -2a)³ + ( c + a -2a)³ = 3(a + b -2c )(b + c -2a) (c + a -2b )
so,
use a³ + b³ + c³ = 3abc
when a + b + c =0
now,
( a + b -2c )³ + ( b + c -2a)³ + ( c + a -2a)³ = 3(a + b -2c )(b + c -2a) (c + a -2b )
Anonymous:
grt answer
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