factorize (a-b)^3+(b-c)^3+(c-a)^3
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Let a-b=x
Let b-c=y
Let c-a=z
Then x+y+z= a-b+b-c+c-a=0
x^3+y^3+z^3=3xyz
=3(a-b)(b-c)(c-a)
=3a-3b+3b-3c+3c-3a
=1
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