Factorize a²-b²-4c²+4bc.
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8
a²-b²-4c²+4bc
= a²-(b²+4c²-4bc)
=a²-[(b)² + (2c)² - 2 x b x 2c]
=a²-(b-2c)²
=(a-b+2c)(a+b-2c)
= a²-(b²+4c²-4bc)
=a²-[(b)² + (2c)² - 2 x b x 2c]
=a²-(b-2c)²
=(a-b+2c)(a+b-2c)
Answered by
3
a²-b²-4c²+4bc
= a²-(b²+4c²-4bc)
=a²-[(b)² + (2c)² - 2 x b x 2c]
=a²-(b-2c)²
=(a-b+2c)(a+b-2c)
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