factorize a³-125-2a+10
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Required Answer:-
Given to Factorise:
- a³ - 125 - 2a + 10
Solution:
We have,
a³ - 125 - 2a + 10
= (a)³ - (5)³ - 2(a - 5)
= (a - 5)(a² + 5a + 25) - 2(a - 5)
Take (a - 5) as common,
= (a - 5)[a² + 5a + 25 - 2]
= (a - 5)(a² + 5a + 23)
Hence, the factorised form of the polynomial is (a - 5)(a² + 5a + 23)
Identity Used:
- x³ - y³ = (x - y)(x² + xy + y²)
More Identities:
- (a + b)² = a² + 2ab + b²
- (a - b)² = a² - 2ab + b²
- (a + b)³ = a³ + 3ab(a + b) + b³
- (a - b)³ = a³ - 3ab(a - b) - b³
- a² - b² = (a + b)(a - b)
- a³ + b³ = (a + b)(a² - ab + b²)
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