Question

Factorize ab(c^2+d^2)-a^2cd-b^2cd

Answer 1

= abc^2+abd^2-a^2cd-b^2cd
= abc^2-a^2cd+abd^2-b^2cd
=ac(bc-ad)+bd(ad-bc)
=ac(bc-ad)-bd(bc-ad)
=(ac-bd)(bc-ad)

Answer 2

Answer:

(ac-bd) (bc-ad)

Step-by-step explanation:

$=> ab( c^{2} +d^{2} ) - a^{2} cd - b^{2} cd$

$=> abc^{2}+ abd^{2} - a^{2} cd - b^{2} cd$

$=> abc^{2} - a^{2} cd - b^{2} cd+abd^{2}$

$=> ac(bc-ad) - bd(bc-ad)$

$=> (ac-bd) (bc-ad)$

hope it is clear