Question

Factorize and solve the sum of zeroes and the product of zeroes for it:
4u²+8u

Answer 1

p(x) = 4u²+8u

4u ( u + 2 ) = 0

[4u + 0 ] [ u + 2 ] ------> factorized form

hence ,

u = 0

u = -2

Here ,

a = 4

b = 8

c = 0

Relation between zeros and its coefficients :-

Sum of zeroes = 0 + -2 = - 2

= -b/a = -8/4 = -2

Product of zeroes = 0 x -2 = 0

= c/a = 0/4 = 0