Question

Factorize by splitting middle term y²+ 2y -255​

Answer 1

Answer:

y=15 or y= -17

Step-by-step explanation:

y²+2y -255=0

comparing equation by ax²+bx+c=0

a=1, b=2, c= -255

therefore multiplying a and c

1× -255 = -255

therefore -255 = 17× -15

17-15 =2

therefore y²+2y -255 =0 can be rewritten as

y²+17y-15y-255=0 (taking common from the pairs)

y(y+17) -15(y+17) =0

(y-15)(y+17) =0

y-15=0 y+17=0

y=15 y= -17

Answer 2

Answer:

y²+ 2y -255

Here

a= y

b= 2y

c= 255

P=a×c (product= ac)

s=b (sum = b)

we've to make 2y into 2 parts whose sum should be 2 and product should be -255

For that we've to check factors tabel of 255,and 15×17 makes 255,also 17-5=2, therefore 15 and 17 are our numbers

y²+15y-17y-255

(y×y+15×y)-(17×y-255)

y(y+15)-17(y+15)

(y+15)(y-17)

hope it helps