Factorize by taking out the common factors x3(2x-3y)-x2(2x-3y)square
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question is 3x(2x-3y)-2x(2x-3y)²
=> (2x-3y)(3x-2x(2x-3y))
=>(2x-3y)(3x-4x²-6xy)
if the question is
x³(2x-3y)-x²(2x-3y)²
=>x²[x(2x-3y)-(2x-3y)² ]
=>x²[(2x-3y)(x-2x-3y)]
=>x²[(2x-3y)(-x-3y)]
=>-x²(2x-3y)(x+3y)
=> (2x-3y)(3x-2x(2x-3y))
=>(2x-3y)(3x-4x²-6xy)
if the question is
x³(2x-3y)-x²(2x-3y)²
=>x²[x(2x-3y)-(2x-3y)² ]
=>x²[(2x-3y)(x-2x-3y)]
=>x²[(2x-3y)(-x-3y)]
=>-x²(2x-3y)(x+3y)
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