factorize by using identity (A) 4a^2 - 25b^2 (b ) x^2+8x+16
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1) 4a^2 - 25b^2
= (2a)^2 - (5b)^2
= (2a +5b) (2a-5b)
By using: a^2 -b^2 = (a+b) (a-b)
2) x^2 +8x +16
= x^2 + 2× x×4 + 4^2
= (x+4)^2
By using: a^2 + 2ab + b^2= (a+b)^2
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= (2a)^2 - (5b)^2
= (2a +5b) (2a-5b)
By using: a^2 -b^2 = (a+b) (a-b)
2) x^2 +8x +16
= x^2 + 2× x×4 + 4^2
= (x+4)^2
By using: a^2 + 2ab + b^2= (a+b)^2
Please mark it brainliest
pavan203:
Thanku so much akka
Answered by
4
Heya user
Here's your answer:-
(A) 4a^2-25b^2
⇒(2a)²-(5b)²
⇒(2a+5b) (2a-5b) (∵a²-b²=(a+b) (a-b)
(B) x²+8x+16
⇒x²+2×4+1+4²
⇒(x+4)² (∵ a²+2ab+b²)
Have a great day ahead ^_^
Here's your answer:-
(A) 4a^2-25b^2
⇒(2a)²-(5b)²
⇒(2a+5b) (2a-5b) (∵a²-b²=(a+b) (a-b)
(B) x²+8x+16
⇒x²+2×4+1+4²
⇒(x+4)² (∵ a²+2ab+b²)
Have a great day ahead ^_^
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