if the circumference of two circles are in the ratio 2: 3 ,what is the ratio of their areas?
ashishverma123:
area must be 4:9
how?
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Answered by
0
Area must be 2:3 .thanks for the question
Answered by
1
let C.S.A be 2*C.s.A and 3*CSA
CSA 1/CSA 2=2 * 2 pi r /3* 2 pi r
= 4 pi r/6 pi r
=4 r/6 r
thus radius 1 = 4r and radius 2 = 6r
Area 1/Area 2=pi (4r)^2 / pi (6r)^2
=16 r^2/36 r^2
= 4/9
thus ratio 4:9
CSA 1/CSA 2=2 * 2 pi r /3* 2 pi r
= 4 pi r/6 pi r
=4 r/6 r
thus radius 1 = 4r and radius 2 = 6r
Area 1/Area 2=pi (4r)^2 / pi (6r)^2
=16 r^2/36 r^2
= 4/9
thus ratio 4:9
4:9 is same as 2:3
no
2:3 can be 4:6
sorry bro
app ne dono cirles ka radius same kaise lai lia
??
i took radius 1 as 4r while radius 2 as 6r
ok
i was right...
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