Question

factorize completely <br /><br /><br />$8 {x}^{2}y - 18 {y}^{3}$<br />

Answer 1

hiii,

8x^y - 18y^3
=2y(4x^2 - 9y^2)
=2y[(2x)^2 - (3y)^2]
=2y(2x + 3y)(2x - 3y)

hope helps

Answer 2

given   8 x² y - 18 y³
            2 y (4 x² - 9 y²)
            2 y [ (2x)² - (3y)² ]
            2 y [ (2x + 3 y) * (2x - 3 y) ]

So factors are :  2 , y , (2x + 3y), (2x - 3y).