Question

Factorize each of the following expressions:
a³+8b³+64c³-24abc

Answer 1

Answer:

a×a×a+2×2×2b×b×b×+32×32-2×2×2×2×2×2×a×b×c

Answer 2

Answer:

a³-8b³-64c³-24abc

= a³+(-2b)³+(-4c)³-3*a*-2b*-4c

= (a-2b-4c)(a²+(-2b)²+(-4c)²(-2*a*-2b)(-2*-2b*-4c)(-2*a*-4c))

= (a-2b-4c)(a²+4b²+16c²+4ab-8bc+8ac)

Step-by-step explanation:

=(a)³-(2b)³-(4c)³-3(a)(2b)(4c)

=[a³-b³-c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

=(a)³-(2b)³-(4c)³-3(a)(2b)(4c)=(a+2b+4c)[(a)²+(2b)²+(4c)²-(a)(2b)-(2b)(4c)-(4c)(a)

=(a+2b+4c)(a²+4b²+16c²-2ab-8bc-4ca)