Question

Factorize:
(i) 12x2–7x+1
​

Answer 1

$\huge\red{ⓐⓝⓢⓦⓔⓡ}$

Using the splitting the middle term method,

We have to find a number whose sum = -7 and product =1×12 = 12

We get -3 and -4 as the numbers [-3+-4=-7 and -3×-4 = 12]

$12x^2–7x+1= 12x^2-4x-3x+1$

$= 4x(3x-1)-1(3x-1)$

$= (4x-1)(3x-1)$

Answer 2

Solution___

12x² - 7x + 1

12x² - 7x + 1

12x² - 7x + 1 = we can find two numbers such that pq = 12 x 1 = 12 and p + q = -7

12x² - 7x + 1 = we can find two numbers such that pq = 12 x 1 = 12 and p + q = -7= Here, 12x² - 7x + 1 = 12x² - 4x - 3x + 1

12x² - 7x + 1 = we can find two numbers such that pq = 12 x 1 = 12 and p + q = -7= Here, 12x² - 7x + 1 = 12x² - 4x - 3x + 1= 4 x ( 3x - 1 ) - 1 ( 3x - 1 )

12x² - 7x + 1 = we can find two numbers such that pq = 12 x 1 = 12 and p + q = -7= Here, 12x² - 7x + 1 = 12x² - 4x - 3x + 1= 4 x ( 3x - 1 ) - 1 ( 3x - 1 )= ( 3x - 1 ) ( 4x - 1 )

12x² - 7x + 1 = we can find two numbers such that pq = 12 x 1 = 12 and p + q = -7= Here, 12x² - 7x + 1 = 12x² - 4x - 3x + 1= 4 x ( 3x - 1 ) - 1 ( 3x - 1 )= ( 3x - 1 ) ( 4x - 1 )_________________________________________________________

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