Question

factorize:-
i)6ab-b^2+12ac-2bc
ii)9(2a-b)^2-4(2a-b)-13​

Answer 1

i) b(6a-b) + 2c(6a-b)

= (b+2c)(6a-b)

ii) Let 2a-b = x

The equation will be

9x^2 - 4x - 13

= 9x^2 + 9x - 13x - 13

= 9x(x+1) - 13(x+1)

=(9x-13)(x+1)

=9{(2a-b)-13}{(2a-b)+1}