Math, asked by balwantbankoti, 2 months ago

Factorize:-
(i) 9-x^6+2x^3y^3-y^6
(ii) 75a^6b^2-108ab^4

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Answers

Answered by anindyaadhikari13
13

Solution:

Factorisation of 9 - x⁶ + 2x³y³ - y⁶

= 9 - [x⁶ - 2x³y³ + y⁶]

= 9 - [(x³)² - 2 × x³ × y³ + (y³)²]

= 9 - [x³ - y³]². [(a - b)² = a² - 2ab + b²]

= (3)² - (x³ - y³)² [a² - b² = (a + b)(a - b)]

= (3 + x³ - y³)(3 - x³ - y³) (Answer)

Factorisation of 75a⁶b² - 108ab⁴

= 3ab²(25a⁵ - 36b²)

This cannot be factorised more.

Answer: 3ab²(25a⁵ - 36b²)

Final Answers:

  • (3 + x³ - y³)(3 - x³ + y³)
  • 3ab²(25a⁵ - 36b²)

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