Question

factorize it...................................

Answer 1

we cannot factorize it because it has no solution according to the quadratic discriminate b^2-4(a)(c)
here b=1 a=1 c=1
1^2-4(1)(1) =1-4
=-3
so it has no solution
PLZ MARK ME AS A BRAINLIST

Answer 2

it has imaginary roots as
D = b^2 -4ac = 1 - 4*1*1 = -3 < 0

roots of the eq are =( - b +- √b^2 -4ac)/2a

=( -1 +-√-3)/2
=( -1 + √3i)/2 and (-1 - √3i)/2 where I = iota =√-1

so factors of eq are
(x-alhpa)(x-beta) where aphla and beta are roots of the eq
(X - ( -1 + √3i)/2)(X - ( -1 - √3i)/2)
ans