Factorize it
x(x^3-y^3)+3xy(x-y)
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x(x^3-y^3)+3xy(x-y)
=x(x-y)(x^2+xy+y^2)+3xy(x-y)
=x(x-y)[x^2+xy+y^2+3y]
=x(x-y)(x^2+xy+y^2)+3xy(x-y)
=x(x-y)[x^2+xy+y^2+3y]
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