Question

factorize : m^3-3m^2+4

Answer 1

Answer:

$(m + 1)(m - 2) {}^{2}$

Step-by-step explanation:

$m {}^{3} +3 m {}^{2} + 4$

$m {}^{3} + m {}^{2} - 4m + 4$

$m {}^{2} (m + 1) - 4(m {}^{2} - 1)$

using a^2 -b^2 = (a- b) (a+ b)

$m {}^{2} (m + 1) - 4(m - 1)(m + 1)$

factor out (m + 1)

$(m + 1)(m {}^{2} - 4(m - 1))$

$(m + 1)(m {}^{2} - 4m + 4)$

using a^2 -2ab+b^2 = (a-b)^2

$(m + 1)(m - 2) {}^{2}$