.What is the elastic and inelastic collision. Write 2 characteristics of each case.
show that an elastic one dimensional collision, the relative velocity of approach is
equal to the relative velocity of separation.
Answers
Answered by
59
Explanation:
Here, for collision to happen, V
1
>V
2
velocity of approach =U
1
−U
2
[velocity w.r.t]
velocity of separation =V
2
−V
2
[vel.w.r.t]
As we know,
Coefficient of restitution (e) =
vel.ofapproach
vel.ofseperation
∴e=
U
1
−U
2
V
2
−V
1
........(1)
and, e=1 for elastic collision.
1=
U
1
−U
2
V
2
−V
1
U
1
−U
2
=V
2
−V
1
.
So,
velocity of approach=velocity of separation
solution
Answered by
6
Answer:
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