Question

.What is the elastic and inelastic collision. Write 2 characteristics of each case.

show that an elastic one dimensional collision, the relative velocity of approach is

equal to the relative velocity of separation.​

Answer 1

Explanation:

Here, for collision to happen, V

1

>V

2

velocity of approach =U

1

−U

2

[velocity w.r.t]

velocity of separation =V

2

−V

2

[vel.w.r.t]

As we know,

Coefficient of restitution (e) =

vel.ofapproach

vel.ofseperation

∴e=

U

1

−U

2

V

2

−V

1

........(1)

and, e=1 for elastic collision.

1=

U

1

−U

2

V

2

−V

1

U

1

−U

2

=V

2

−V

1

.

So,

velocity of approach=velocity of separation

solution

Answer 2

Answer:

$\sqrt{52 \times 26} \: \\ \\ thank \: you \: for \: free \: point$

Thank you for free point