Question

factorize n^2-3n-40 ​

Answer 1

${x}^{2} - 3x - 40 = 0$

${x}^{2} -8x + 5x - 40 = 0$

$x(x - 8) + 5(x - 8) = 0$

$(x - 8)(x + 5) = 0$

Mate ,this is your answer..Hope it helped

Answer 2

$\bold{Answer:}$

$n^2-3n-40=(n-8)(n+5)$

$\bold{Step} - \bold{by} - \bold{step\ explanation:}$

$n^2-3n-40 \\ \\ n^2-8n+5n-40 \\ \\ n(n-8)+5(n-8) \\ \\ (n-8)(n+5)$