Question

factorize n2 + 201n - 2110 = 0​

Answer 1

Answer:

$to \: factorize = n {}^{2} + 201n - 2110 \\ and \: n {}^{2} + 211n - 10n - 2110 \\ and \: n(n + 211) - 10(n + 211) \\ and \: (n - 10)(n + 211) \\ hence \: factorized$