Question

factorize of b(c-d)²-a(d-c)+5c-5d​

Answer 1

b(c-d)2-a(d-c)+5c-5d

b (c-d)2-a(d-c)+5(c+d)

now here we can write -a(d-c) as a(c-d)

b(c-d)2+a(c-d)+5(c-d)

take (c-d) common

(c-d)[b(c-d)+a+5]

(c-d)[bc-bd +a+5]

Answer 2

Answer:

(bc-ad) (ac-bd) is the correct answer