Question

factorize p^3+27q^3+125 r^3-45 pqr​

Answer 1

$= {p}^{3} + 27 {q}^{3} + 125 {r}^{3} - 45pqr \\ = {p}^{3} + {(3q)}^{3} + {(5r)}^{3} - 3(p \times 3q \times 5r) \\ = {(p + 3q + 5r)}^{3}$

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