Math, asked by singhbasant852, 1 year ago

Factorize (p-q)cube+(q-r)cube+(r-p)cube




Answers

Answered by ArifWani
1
Given:-

(p-q)^3 + (q-r)^3 + (r-p)^3
we know that
a^3 + b^3 + c^3 = 3abc if a + b + c =0

Here
(p-q) + (q-r)+(r-p) = 0
p-q+q-r+r-p=0
0=0

HENCE:-
(p-q)^3 +(q-r)^3 +(r-p)^3 = 3 (p-q)(q-r)(r-p)
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