Factorize :
p³(q-r)³+q³(r-p)³+r³(p-q)³
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Answered by
28
HEY MATE
HERE'S THE RIGHT ANSWER
If x+y+z=0
then,
x^3+y^3+z^3=3xyz.......(1)
Now according to the question,
let,
x=p-q
y=q-r
z=r-p
x+y+z = p-q+q-r+r-p =0
Therefore,
using (1)
x^3+y^3+z^3= 3xyz
(p-q)^3+(q-r)^3+(r-p)^3
3(p-q)(q-r)(r-p)
HOPE IT HELPS
PLEASE MARK IT AS BRAINLIEST ANSWER
HERE'S THE RIGHT ANSWER
If x+y+z=0
then,
x^3+y^3+z^3=3xyz.......(1)
Now according to the question,
let,
x=p-q
y=q-r
z=r-p
x+y+z = p-q+q-r+r-p =0
Therefore,
using (1)
x^3+y^3+z^3= 3xyz
(p-q)^3+(q-r)^3+(r-p)^3
3(p-q)(q-r)(r-p)
HOPE IT HELPS
PLEASE MARK IT AS BRAINLIEST ANSWER
AditiYadav1999:
Thank u so much
Answered by
9
p-r^3 in common and p^3+q^3and (p-q)^3
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