factorize p⁴-81q⁴
quickly plzzzzzz
Answers
Answered by
9
Given Equation is p^4 - 81q^4
= > (p)^2 - (9q^2)^2
= > (p^2 + 9q^2)(p^2 - 9q^2)
= > (p^2 + 9q^2)((p)^2 - (3q)^2)
We know that a^2 - b^2 = (a + b)(a - b)
= > (p^2 + 9q^2)(p + 3q)(p - 3q).
Hope this helps!
= > (p)^2 - (9q^2)^2
= > (p^2 + 9q^2)(p^2 - 9q^2)
= > (p^2 + 9q^2)((p)^2 - (3q)^2)
We know that a^2 - b^2 = (a + b)(a - b)
= > (p^2 + 9q^2)(p + 3q)(p - 3q).
Hope this helps!
siddhartharao77:
:-)
Answered by
9
Hay!!
Dear friend -
______________________________________
P^4-81q^4
=> (p²)²-(9q²) ²
=> Now we used formula a²-b²
so,
(p²-9q²) (p²+9q²)
=> (p-3q) (p+3q) (p²+9q²)
I hope it's help you
Dear friend -
______________________________________
P^4-81q^4
=> (p²)²-(9q²) ²
=> Now we used formula a²-b²
so,
(p²-9q²) (p²+9q²)
=> (p-3q) (p+3q) (p²+9q²)
I hope it's help you
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