Question

Factorize:-
(Please give proper solution)

Answer 1

Answer:

=a^2-b^2+2bc-c^2

=a^2-(b^2-2bc+c^2)

= a^2-(b-c) ^2

={a-(b-c) }* {a+(b-c) }

= (a-b+c) *(a+b-c)

Answer 2

Step-by-step explanation:

We Have :-

$a^{2} - b^{2} + 2bc - c^{2}$

To Find :-

$factorise \: it$

Identities used :-

$a^{2} - b^{2} = (a + b)(a - b) \\ \\ \\ (a - b)^{2} = a^{2} + b^{2} - 2ab$

Solution :-

$a^{2} - b^{2} + 2bc - c^{2} \\ \\ \\ a^{2} - (b^{2} + 2bc - c^{2} ) \\ \\ \\ using \: identity \\ \\ \\ a^{2} - (b - c) ^{2} \\ \\ \\ again \: using \: another \: identity \\ \\ \\ (a - (b - c))(a + (b - c))$