Factorize: square root 2x^2+3x+square root 2
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Hello Mate!
=> √2x² + 3x + √2 = 0
So, √2x² × √2 = 2x²
This means that we have to split middle term in such a way thag its product is equal to product of first and second term.
=> √2x² + 2x + x + √2 = 0
=> √2x( x + √2 ) + 1( x + √2 ) = 0
=> ( √2x + 1 )( x + √2 ) = 0
However if you wanna find root of x thenz
Hence, x = - 1/√2 or - √2/2 and - √2
Have great future ahead!
=> √2x² + 3x + √2 = 0
So, √2x² × √2 = 2x²
This means that we have to split middle term in such a way thag its product is equal to product of first and second term.
=> √2x² + 2x + x + √2 = 0
=> √2x( x + √2 ) + 1( x + √2 ) = 0
=> ( √2x + 1 )( x + √2 ) = 0
However if you wanna find root of x thenz
Hence, x = - 1/√2 or - √2/2 and - √2
Have great future ahead!
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