Question

factorize
$1)2y {}^{2} - 11y + 5 \: \: \: \: \: \: \: 2)x {}^{2} - 2x - 80$
please solve this problem please help me​

Answer 1

Step-by-step explanation:

$\bf \huge \underline \blue{Answer:-}$

$\sf \: 1) {2y}^{2} - 11y + 5$

$\sf \: {2y}^{2} - 10y - y + 5$

$\sf \: 2y(y - 5) - 1(y - 5)$

$\sf \: (2y - 1)(y - 5)$

therefore,

y = 1/2 and y = 5

$\sf \: 2) {x}^{2} - 2x - 80$

$\sf \: {x}^{2} + 8x - 10x - 80$

$\sf \: x(x + 8) - 10(x + 8)$

$\sf \: (x - 10)(x + 8)$

therefore,

x = 10 and x = -8