Question

Factorize
$6 \sqrt{3x {}^{2} } - 47x + 5 \sqrt{3}$
$\sqrt{3x {}^{2} } + 10x + 8 \sqrt{3}$
$\sqrt{5x { }^{2} } + 2x - 3 \sqrt{5}$
$7x {}^{2} + 2 \sqrt{mn} + 2$
$5 \sqrt{5x {}^{2} } + 20x + 3 \sqrt{5}$
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Answer 1

Answer:

Step-by-step explanation:

6\/3x^2-47x+5\/3

6\/3x^2-45x-2x+5\/3

3\/3x(2x-5\/3x) - 1(2x-5\/3)

(3\/3x - 1)(2x - 5\/3x)