factorize
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Answered by
1
Step-by-step explanation:
(6x2−21x)+(−10x+35)

3x-5
3x\left(2x-7\right)-5\left(2x-7\right)3x(2x−7)−5(2x−7)

2x-7
\left(2x-7\right)\left(3x-5\right)(2x−7)(3x−5)
Answered by
0
Answer:
I started by factoring out a negative one.
62+31x−35 −1(6x2−31x+35)
From there, you can split the middle term to accommodate both terms and get the same internal expression. (Some guess and check involved)
6x2−21x−10x+35
3x(2x−7)−5(2x−7)
From there you combine them to get
(3x−5)
(2x−7)
and there is your factored form.
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