Math, asked by ghoshrakhi2020, 11 months ago

factorize 6x^{2}-31x+35

Answers

Answered by 008sar
1

Step-by-step explanation:

(6x2−21x)+(−10x+35)

3x-5

3x\left(2x-7\right)-5\left(2x-7\right)3x(2x−7)−5(2x−7)

2x-7

\left(2x-7\right)\left(3x-5\right)(2x−7)(3x−5)

Answered by Hemu1432
0

Answer:

I started by factoring out a negative one.

62+31x−35 −1(6x2−31x+35)

From there, you can split the middle term to accommodate both terms and get the same internal expression. (Some guess and check involved)

6x2−21x−10x+35

3x(2x−7)−5(2x−7)

From there you combine them to get

(3x−5)

(2x−7)

and there is your factored form.

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