Math, asked by Herorjdhf, 1 year ago

Factorize :
x {}^{2}  - 10xy + 16y {}^{2}  - z {}^{2}  + 6yz

Answers

Answered by JinKazama1
10
Final Answer : (x-2y-z) (x-8y+z)

Steps:
1)
 {x}^{2}  - 10xy + 16 {y}^{2}  -  {z}^{2}  + 6yz \\  =   { x}^{2}  - 10xy + 25 {y}^{2}  - 9 {y}^{2}  -  {z}^{2} \\   + 6yz \\  =  {(x - 5y)}^{2}  - ( {z}^{2} - 6yz +  9 {y}^{2} ) \\  =  {(x - 5y)}^{2}  -  {(z - 3y)}^{2}  \\  =  (x - 5y - z + 3y) \\  \times ( x - 5y + z - 3y) \\  = (x - 2y - z)(x - 8y + z)
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