Question

factorize the expression x³-6x²+11x-6​

Answer 1

here constant term(c)=-6

factors of c=±1,±2,±3,±6

by trial and error method,

f(1)=0

1³-6.1²+11.1-6

=1-6+11-6

=0

thus,by factor theorem,

(x-1) is a factor of the given f(x).

on dividing,f(x) by (x-1)

we get x²-5x+6

so f(x)=(x-1)(x²-5x+6)

=(x-1)(x-2)(x-3). (Answer)