Factorize the following:√5 x2 + 4x - √5
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let’s see
(x - 2 + i) ( x- 2 - i) =( (x-2) + i ) ( (x -2) -i) =
(x -2)^2 - i^2 since (a -b) (a +b) = a^2 - b^2
= x^2 - 4x +4 + 1 = x^2 - 4x +5,
so no, that doesn’t seem right.
how about the quadratic formula
r = (-4 + sqrt(16 - 20))/2 = (-4 + 2i)/2 = i - 2
and
r = (-4 - 2i)/2 = -i - 2
It looks more like x^2 + 4x + 5 = ( x - (i -2)) (x - (-i -2)) = (x - i + 2) (x + i + 2)
= (x + 2 - i) (x + 2 + i)
Let’s check that:
= ((x + 2) -i) ((x + 2) +i ) = (x+2)^2 - i^2 = x^2 +4x + 4 - (-1) = x^2 + 4x + 5
Looks good to me
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