Math, asked by anandhvf1977, 10 months ago

factorize the following by splitting middle
a) 3x^2+19x+30
b) 2√2x^2+9x+5√2
c) 4x^2-13x+10

Answers

Answered by BRAINLYADDICTOR

⭐MARK BRAINLIST⭐

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$a)3x {}^{2} + 19 x + 30 = 0 \\ = > 3 x{}^{2} + 9x + 10x + 30 = 0 \\ = > 3x(x + 3) + 10(x + 3) = 0 \\ = > (x + 3)(3x + 10) = 0\\ = > x = - 3(or) x = - 10 \div 3$

$b)2 \sqrt{2}x {}^{2} + 9x + 5 \sqrt{2} = 0 \\ = > 2 \sqrt{2} x {}^{2} + 4x + 5x + 5 \sqrt{2} = 0\\ = > 2 \sqrt{2}x (x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0 \\ = > (x + \sqrt{2} )(2 \sqrt{2}x + 5) = 0 \\ = > x = - \sqrt{2} (or)x = - 5 \div 2 \sqrt{2}$

$c)4 x{}^{2} - 13x + 10 = 0 \\ = > 4x {}^{2} - 8x - 5x + 10 = 0 \\ = > 4x(x - 2) - 5(x - 2) = 0 \\ = > (x - 2)(4x - 5) = 0 \\ = > x = 2(or)x = 5 \div 4$

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Answered by NIKKIASHBN

Answer:

$a)3x {}^{2} + 19 x + 30 = 0 \\ = > 3 x{}^{2} + 9x + 10x + 30 = 0 \\ = > 3x(x + 3) + 10(x + 3) = 0 \\ = > (x + 3)(3x + 10) = 0\\ = > x = - 3(or) x = - 10 \div 3$

$c)4 x{}^{2} - 13x + 10 = 0 \\ = > 4x {}^{2} - 8x - 5x + 10 = 0 \\ = > 4x(x - 2) - 5(x - 2) = 0 \\ = > (x - 2)(4x - 5) = 0 \\ = > x = 2(or)x = 5 \div 4$

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factorize the following by splitting middle a) 3x^2+19x+30b) 2√2x^2+9x+5√2c) 4x^2-13x+10​

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⭐MARK BRAINLIST⭐

factorize the following by splitting middle
a) 3x^2+19x+30
b) 2√2x^2+9x+5√2
c) 4x^2-13x+10